Homework Help - Math

[vanshajwore 324]

Can you show how you got that please?

And the answer shows 7/48

I alwaya get wierd answers.

Now i got 10.4 :p

Another try gave me z= 211/2352 omg -_-

Ask someone else man i have not been asked suxh hard questions in my class xD

Can you describe what is the topic about please, it will help i my exams too :D

Edited December 13, 2014 by vanshajwore

[deadmanrising 715]

New question!

 

I need to differntiate this

 

- A cos (at - kx) / at

 

I got this

 

A at sin (at ^ -1( at - kx )

 

Am i right?

Someone please tell me :(

[deadmanrising 715]

(x-y)(x+y)= x^2 - y^2

is it true :P?

x ^ 2 + yx - yx -y ^2

 

Yes its true :p 

[r_GaIaxy2 8,611]

This has got to be the best page in the forum!!! 

Whats 9+10?

[sachet100 1,020]

This has got to be the best page in the forum!!! 

Whats 9+10?

21 :P

actually its 19

Edited December 13, 2014 by sachet100

[r_GaIaxy2 8,611]

21 :P

actually its 19

Well Done!!! or not?!?!?

[The.Skilled.Legend 1,459]

:o  So many numbers

[sachet100 1,020]

Well Done!!! or not?!?!?

 

https://www.youtube.com/watch?v=vsp18UOLveU&list=RDBdFfEOd3ioQ

 

Edited December 13, 2014 by sachet100

[r_GaIaxy2 8,611]

 

https://www.youtube.com/watch?v=vsp18UOLveU&list=RDBdFfEOd3ioQ

 

haha yup

[I.Noob.FX 56]

A chicken farmer has figured out that a hen and a half can lay an egg and a half in a day and a half. How many hens does the farmer need to produce one dozen eggs in six days?

 

 

Solution:

 

the farmer needs 3 hens to produce 12 eggs in 6 days

 

This is a classic problem that many people get wrong because they reason that half of a hen cannot lay an egg, and a hen cannot lay half an egg. However, we can get a satisfactory solution by treating this as a purely mathematical problem where the numbers represent averages.

 

To solve the problem, we first need to find the rate at which the hens lay eggs. The problem can be represented by the following equation, where RATE is the number of eggs produced per hen·day:

 

1½ hens × 1½ days × RATE = 1½ eggs

 

We convert this to fractions thus:

3/2 hens × 3/2 days × RATE = 3/2 eggs

 

Multiplying both sides of the equation by 2/3, we get:

1 hen × 3/2 days × RATE = 1 egg

 

Multiplying both sides of the equation again by 2/3 and solving for RATE, we get:

RATE = 2/3 eggs per hen·day

 

Now that we know the rate at which hens lay eggs, we can calculate how many hens (H) can produce 12 eggs in six days using the following equation:

 

H hens × 6 days × 2/3 eggs per hen·day = 12 eggs

 

Solving for H, we get:

H = 12 eggs /(6 days × 2/3 eggs per hen·day) = 12/4 = 3 hens

 

Therefore, the farmer needs 3 hens to produce 12 eggs in 6 days.

 

 

Edited December 14, 2014 by I.Noob.FX

[fahim_the_boss 1,519]

x^2 y^2

[Guest Maserati]

19.

I'm really clever, aren't I? :D

 

 

Oscar at your service   ;)

[Pathfinder 1,690]

I will make you an offer along with 100 other people.

 

In a closed room, with one hundred boxes numbered 1 to 100, i place one hundred pieces of paper, numbered also 1 to 100, but in random boxes. Each of you will now enter the room one at a time, and exit from a different door.

 

You are each allocated a number, from 1 to 100. Upon entering the room, you can check half the boxes only for your number. Once checked, the room resets back to normal for the next person.

 

You are allowed to discuss a strategy before, but no communication is allowed after any one of you enters the room.

 

If each and every one of you finds his or her number, you all win £100. But if just one of you does not find his or her number, you win nothing. To play, each of you pays £1.

 

The questions is, should you take the bet?

[MarineMan2 1,164]

Personally, this sounds like a bad idea. Someone who does not know the answer might reply, and then people would be receiving incorrect answers. Additionally, if you type a math equation into Google, it will answer nearly any question. Or for simpler equations, you could use Google's Calculator.

[sachet100 1,020]

Personally, this sounds like a bad idea. Someone who does not know the answer might reply, and then people would be receiving incorrect answers. Additionally, if you type a math equation into Google, it will answer nearly any question. Or for simpler equations, you could use Google's Calculator.

ya we can use calculator for questions like: 21+35 ........ But we can't search this type of question in google (i think):::::::::

2x-4+4=10+4          

2x=14

2x/2 = 14/2

x= 7

or we can't search for this type of questions::60x-20+50=500... or  this type of questions: A bent is the union of the interior and boundary of a simple quadrilateral such that an interior angle formed by two adjacent edges exceeds 180^o and the interior angle formed by the other two edges exceeds 90^o. Prove that the union of the interior and boundary of an acute triangle can not be the union of a finite number of bents which have disjoint interiors.

 

 

and i know some people are asking stupid questions :mellow:

Edited December 14, 2014 by sachet100

[doughnut2100 763]

True, for most things you could find the answer to it in some math web site. But I guess some people like to check here too now. :lol:

[I.Noob.FX 56]

What is 9/2(3.14)²

[deadmanrising 715]

What is 9/2(3.14)²

Cant you use a calculator?

[slash1524 74]

What is 9/2(3.14)²

9/2(3.14)2

First the exponent,

so 3.14 raised to the power to equals 9.86

then division and multiplication from left to right, so

9/2=4.5

and 4.5x9.86=44.37.

[deadmanrising 715]

New question!

 

I need to differntiate this

 

- A cos (at - kx) / at

 

I got this

 

A at sin (at ^ -1( at - kx )

 

Am i right?

No one can verify if im right? :(

[mdit108 121]

I will make you an offer along with 100 other people.

 

In a closed room, with one hundred boxes numbered 1 to 100, i place one hundred pieces of paper, numbered also 1 to 100, but in random boxes. Each of you will now enter the room one at a time, and exit from a different door.

 

You are each allocated a number, from 1 to 100. Upon entering the room, you can check half the boxes only for your number. Once checked, the room resets back to normal for the next person.

 

You are allowed to discuss a strategy before, but no communication is allowed after any one of you enters the room.

 

If each and every one of you finds his or her number, you all win £100. But if just one of you does not find his or her number, you win nothing. To play, each of you pays £1.

 

The questions is, should you take the bet?

this is interesting... 

[BlitzPanzer12345 241]

what is the differentation of 3x - 4 * cos^3 (x^2) ??

[Tex_Ranger_BMF 5]

what is the differentation of 3x - 4 * cos^3 (x^2) ??

3x - 4 Not a Math question,  cos^3 (x^2) Simplify +(x2) to x 2

Thanks

[I.Devastation 2,053]

I will make you an offer along with 100 other people.

 

In a closed room, with one hundred boxes numbered 1 to 100, i place one hundred pieces of paper, numbered also 1 to 100, but in random boxes. Each of you will now enter the room one at a time, and exit from a different door.

 

You are each allocated a number, from 1 to 100. Upon entering the room, you can check half the boxes only for your number. Once checked, the room resets back to normal for the next person.

 

You are allowed to discuss a strategy before, but no communication is allowed after any one of you enters the room.

 

If each and every one of you finds his or her number, you all win £100. But if just one of you does not find his or her number, you win nothing. To play, each of you pays £1.

 

The questions is, should you take the bet?

"you along with 100 other people" = 101 but 100 boxes? o.O

[Taco 2,820]

There is an app for iOS and for Windows Phones. (Android version will be coming out in early 2015)

 

It's called PhotoMath, look for it in the App Store and download it, it's free.

 

What you do is use the camera in your phone to take a picture of the math problem and it will guide you through all of the steps to solve it so you understand it.

 

Here is the link to it on iTunes: https://itunes.apple.com/us/app/photomath/id919087726?mt=8

 

 

I hope this helps you guys out :)

 

Good luck ;)

Edited December 16, 2014 by Taco