Help!

[newrohan 1,040]

Can someone help me with these questions? I want a detailed explanations please.

1. 

 

 

 

2. 

Edited October 23, 2015 by newrohan

[Sulluinen 111]

Please read the off-topic section rules before creating a topic

[TriNitroToIuene 4,765]

Hmmm, for the first question, factorize that irrational equation given there. Then, once you have the value of m1 and m2, just substitute it in the y = c = whatever and use the triangular coordinate equation.

 

Hold on, lemme try solve it myself.

[newrohan 1,040]

Please read the off-topic section rules before creating a topic

There's no such rule!

[newrohan 1,040]

Here's the solution, but I Can't understand it.

1.

 

 

2.

 

[newrohan 1,040]

I mean, in 2. , Is it some identity which has been used in the first line on term 2 on left side and the term on right side?

[newrohan 1,040]

Omg!!!

???

[I.WalkAlone 548]

In the second step they're bringing (3+√8) from the right to the left side which reduces the power of the polynomial on the left side by 1.

Edited October 23, 2015 by I.WalkAlone

[newrohan 1,040]

 

Anyway, in the second step they're bringing (3+√8) from the right to the left side which reduces the power of the polynomial on the left side by 1.

Still don't get it :l

[Taco 2,820]

Here's the solution, but I Can't understand it.

1.

 

 

2.

 

Dude what grade are you in? I have no idea how to do these things xD

[The_PlayMaker 657]

Dude what grade are you in? I have no idea how to do these things xD

Well I guess those questions are from the chapter "Straight Lines" which a chapter from the 11th grade here in India.

Edited October 23, 2015 by The_PlayMaker

[Zenyth 6,494]

I can probably solve this I wilk give you my solution soon.

[newrohan 1,040]

I can probably solve this I wilk give you my solution soon.

Thanks  :D

[TriNitroToIuene 4,765]

I mean, in 2. , Is it some identity which has been used in the first line on term 2 on left side and the term on right side?

I didn't exactly get the t part in the second sum, seeing that I'm just in 9th grade :ph34r:

 

I came pretty darn close to solving that first sum tho :/

[newrohan 1,040]

I didn't exactly get the t part in the second sum, seeing that I'm just in 9th grade :ph34r:

 

I came pretty darn close to solving that first sum tho :/

I got the t part, but not the first part! Can you explain the first part? :D

[BlueDragon_tamki 3,204]

?!

[TriNitroToIuene 4,765]

I got the t part, but not the first part! Can you explain the first part? :D

2/(3-root 8) is an irrational number, you need to rationalise it first.

 

therefore, you have to do - 

 

2/(3-root 8) X (3+root8)/(3+root8)

 

3-root8 and 3+root8 will result to 1 on multiplication (Identity - [a+b][a-b] = a² - b²)

 

so, 3² - root8² = 9-8 = 1, so the denominator is 1.

 

Then, on multiplying the numerators, you get 2(3+root8)

 

The second term is 3-root8, so in order to make it positive, you carry the computational sign to the power.

 

So, bringing the 3+root8 on the RHS to the lhs, we divide the WHOLE LHS by 3+root8.

 

Now, applying laws of exponents, we dock of the +1 from the powers of each term, leaving us with, er, the part before the t.

 

Hope you understood, bro.

 

Also, could you explain how you do the sum beyond the t? This seems pretty interesting :D

 

EDIT - I figured it out, I'm just too lazy to see how (rootT-1/rootT)² = 1. Could you show me? :P

Edited October 23, 2015 by TriNitroToIuene

[newrohan 1,040]

 

 

EDIT - I figured it out, I'm just too lazy to see how (rootT-1/rootT)² = 1. Could you show me? :P

Thanks! :D

For the part, we assumed that thing as t.

So, t+1/t+2 Forms

(root t+1/root t)^2

As t+1/t +2 = (root t)^2 + (1/root t)^2 + 2 X t X 1/t

 

Then, (root t + 1/root t)^2 = 0

=(t+1/root t)^2 = 0

(t+1)^2 = 0

t^2 + 1 + 2t = 0

Solving, t=1

[Zenyth 6,494]

I didn't exactly get the t part in the second sum, seeing that I'm just in 9th grade :ph34r:

 

I came pretty darn close to solving that first sum tho :/

Ha I'm in 12th. ;)

[TriNitroToIuene 4,765]

=(t+1/root t)^2 = 0

(t+1)^2 = 0

t^2 + 1 + 2t = 0

Solving, t=1

Wait, how did root t suddenly metamorphose into t? And I didn't get how that became (t+1)²

[r_L-E-O-P-A-R-D-2003 657]

Hmmm, for the first question, factorize that irrational equation given there. Then, once you have the value of m1 and m2, just substitute it in the y = c = whatever and use the triangular coordinate equation.

 

Hold on, lemme try solve it myself.

what language is that

[TriNitroToIuene 4,765]

what language is that

The language of math, k?

[r_L-E-O-P-A-R-D-2003 657]

The language of math, k?

ok

[newrohan 1,040]

Wait, how did root t suddenly metamorphose into t? And I didn't get how that became (t+1)²

Using a^2 + b^2 + 2ab = (a+b )^2

BTW, I still did not get how 2nd term changed

Edited October 23, 2015 by newrohan

[TriNitroToIuene 4,765]

Using a^2 + b^2 + 2ab = (a+b )^2

1. Still didn't get it.

2. It's root t MINUS 1/root t, not plus.