4=3 .. Is It Correct?

[Zenyth 6,494]

Consider a-b=c.

We can put the equation as..

4a-3a+3b-4b=4c-3c

Rearranging,

4a-4b-4c=3a-3b-3c

4(a-b-c)=3(a-b-c)

Cancelling out factor term (a-b-c).

4=3, hence proved.

 

Is there any mistake.. or is it correct? :P

Find out any error and comment or else you agree that 4=3 from now on! :lol:

 

 

 

Found this on brilliant.org, it's a fun problem.

 

[jokersus.cava 1,503]

You said "a-b=c". Rearrange "c" and you get a-b-c = 0

a-b-c=0, therefore 4(a-b-c) = 4x0 = 0 and 3(a-b-c) = 3x0 = 0

It's a fun problem, though, do you have more?

Edited November 29, 2015 by jokersus.cava

[beaku 2,656]

Exactly what Joker said. Cancellation law only applies if the factor is not 0

[MandolinMarc 874]

No it isn't correct, you're welcome.

[drazeruzumaki 5,021]

4= 3 is wrong  , 3=4 is da right one k?

u dont need to thank me

Edited November 29, 2015 by drazeruzumaki

[Reeco9 1,567]

You said "a-b=c". Rearrange "c" and you get a-b-c = 0

a-b-c=0, therefore 4(a-b-c) = 4x0 = 0 and 3(a-b-c) = 3x0 = 0

This ^

 

You're basically cancelling 0 from both sides, which doesn't work.

It's not 4 = 3, it's actually 4 x 0 = 3 x 0, which is correct.

[DragonOfStorms 2,706]

Well, 4 to the power of 0 = 3 to the power of 0, so maybe...

[ariking777 940]

Zenith - same thing can be done (it'll be wrong, but it's the same logic fallacy) with exponents:

 

3^0 = 1 = 4^0

 

Get the 0th root out of everything, and: 3 = 1 = 4.

 

 

Your mistake is that many algebra techniques don't apply to 0. Taking roots out of equations' sides, factoring, dividing, and many more. 0 can't be a factor.. Common sense can tell you the same.

 

 

 

 

Well, 4 to the power of 0 = 3 to the power of 0, so maybe...

?

 

According to that, all real numbers (and perhaps imaginary too) are the same. I mean, any real number other than zero equals one when raised to the power of zero.

 

 

 

In fact - to all the math geeks around, I have a question to which I haven't ever found a clear answer, and I like debating about: What's i to the power of 0?

Edited November 29, 2015 by ariking777

[Zenyth 6,494]

Zenith - same thing can be done (it'll be wrong, but it's the same logic fallacy) with exponents:

 

3^0 = 1 = 4^0

 

Get the 0th root out of everything, and: 3 = 1 = 4.

 

 

Your mistake is that many algebra techniques don't apply to 0. Taking roots out of equations' sides, factoring, dividing, and many more. 0 can't be a factor.. Common sense can tell you the same.

 

 

 

 

?

 

According to that, all real numbers (and perhaps imaginary too) are the same. I mean, any real number other than zero equals one when raised to the power of zero.

 

 

 

In fact - to all the math geeks around, I have a question to which I haven't ever found a clear answer, and I like debating about: What's i to the power of 0?

(I)^0 = (-1)^1/2.0 =1

[Zenyth 6,494]

You said "a-b=c". Rearrange "c" and you get a-b-c = 0

a-b-c=0, therefore 4(a-b-c) = 4x0 = 0 and 3(a-b-c) = 3x0 = 0

It's a fun problem, though, do you have more?

Yah you're correcto. If we do 0÷0 it becomes indeterminate. I'll try to find more problems. ;)

[GHOST68INVINCIBLE 152]

Umm.....

[BlueDragon_tamki 3,204]

Umm.....

[Zenyth 6,494]

Umm.....

Noooooob

 

JK

[GHOST68INVINCIBLE 152]

Noooooob

JK

Don't we call people who are not good in multiplayer games noobs?

[momy950666 960]

Exactly what Joker said. Cancellation law only applies if the factor is not 0

[MessagerAngel 33]

Why are you guys even talking about this?!

[MessagerAngel 33]

Why are you guys even talking about this?!

[deadmanrising 715]

This is wrong because when rearranging to find a solution to must always have a coefficient to work with

[Spartan_28 347]

Don't ask me lol im not a math guy! :P

[minaal345 7]

Consider a-b=c.

We can put the equation as..

4a-3a+3b-4b=4c-3c

Rearranging,

4a-4b-4c=3a-3b-3c

4(a-b-c)=3(a-b-c)

Cancelling out factor term (a-b-c).

4=3, hence proved.

 

Is there any mistake.. or is it correct? :P

Find out any error and comment or else you agree that 4=3 from now on! :lol:

 

 

 

Found this on brilliant.org, it's a fun problem.

 

 I dont understand wht u said but, in 3 there are four letters. T H R E E. so 4=3 maybe.  :mellow:

[suhas_best 334]

Another one is proving 1=2

 

• Let a = b
• a^2 = ab
• a^2 - b^2 = ab - b^2
• (a+b.)(a-b.) = b(a-b.)
• a+b = b
• But as a=b, 2b = b
• Hence, 2=1 #proved

 

Note: I put the dot between b and ) in "b.)" or it turns into b)...

Edited December 11, 2015 by suhas_best

[Zenyth 6,494]

Another one is proving 1=2

 

• Let a = b
• a^2 = ab
• a^2 - b^2 = ab - b^2
• (a+b.)(a-b.) = b(a-b.)
• a+b = b
• But as a=b, 2b = b
• Hence, 2=1 #proved

Note: I put the dot between b and ) in "b.)" or it turns into b)...

Yeah thats similar. You cancelled a-b which is actually 0. :lol:

[canadarules 1,938]

omg you people can't even understand math i could say 10000= 5 if i wanted to

there are several answers that can be made such as what you guys said

what he said is not wrong because you can cancel it but also he can say 1=0 :O

Edited December 11, 2015 by canadarules

[WALLE 15]

Noobs...

[canadarules 1,938]

Noobs...

you meant to start that with a b not a n