Homework Help

[Boeing_787 1,455]

I decided to open this thread to help fellow Tankers with their homework :)

 

Before posting anything in this thread, make sure you are not asking for answers to any test or assignment. This thread is for the sole purpose of HELP. Also, keep in mind that I am an eighth grader. So please only ask for help with homework that is for my grade level, or below.

<3

Edited July 17, 2016 by Boeing_787

[alan023 169]

How many genders are there?

[The-Operator219 1,929]

A grand total of four.

[Boeing_787 1,455]

How many genders are there?

For humans there are two genders - male, and female.

 

Transgender or gender fluid/asexual people are not a different gender, they just choose to not identify with just one gender.

[arnav0506 2,777]

Q. Factorise: a^3 + b^3

Q. A person travels 6km north then 3km West and 4km North. Find his displacement and distance travelled.

Q. Define momentum.

Q. Derive the first equation of motion, v=u+at.

[arnav0506 2,777]

For humans there are two genders - male, and female.

Transgender or gender fluid/asexual people are not a different gender, they just choose to not identify with just one gender.

A grand total of four.

[Boeing_787 1,455]

Q. Factorise: a^3 + b^3

Q. A person travels 6km north then 3km West and 4km North. Find his displacement and distance travelled.

Q. Define momentum.

Q. Derive the first equation of motion, v=u+at.

Lol, read the OP (only grade level 8 or below )

 

2: distance travelled is 13 km, and displacement (distance from starting point) will be about 10.44 km

3: mass times velocity (mv)

 

For the other questions, Google knows best

Edited July 17, 2016 by Boeing_787

[basenji7 1,199]

Q. Factorise: a^3 + b^3

Q. A person travels 6km north then 3km West and 4km North. Find his displacement and distance travelled.

1. a^3 + b^3 = (a+b)(a^2-ab+b^2)

 

2. He travelled 13 km in total, but the amount of distance from his starting to his ending point is (using Pythag) sqrt(3^2 + 10^2) = sqrt(109). I think that's what you mean by "displacement", but idk I thought it meant the volume taken up by a solid object submerged in a fluid that would otherwise have been taken up by said fluid. 

[o.O_clairvoyant_O.o 18]

Q. Factorise: a^3 + b^3

Q. A person travels 6km north then 3km West and 4km North. Find his displacement and distance travelled.

Q. Define momentum.

Q. Derive the first equation of motion, v=u+at.

we know that, change in velocity/time is acceleration. which can also be stated as derivative of velocity with respect of time when the time is approching 0. so dv/dt=a integrating both sides we get [integration limit]v=at.

now lets say initial velocity was u and final was v. so just put the values and get v-u=at.

[The-Operator219 1,929]

For humans there are two genders - male, and female.

 

Transgender or gender fluid/asexual people are not a different gender, they just choose to not identify with just one gender.

Really? O:

I must record this!

You say that a human can have but one gender, correct?

[Boeing_787 1,455]

Really? O:

I must record this!

You say that a human can have but one gender, correct?

Yes, the only two genders are male and female. Of course there are the confused people...

[The-Operator219 1,929]

I must update my research at once!

[arnav0506 2,777]

1. a^3 + b^3 = (a+b)(a^2-ab+b^2)

 

2. He travelled 13 km in total, but the amount of distance from his starting to his ending point is (using Pythag) sqrt(3^2 + 10^2) = sqrt(109). I think that's what you mean by "displacement", but idk I thought it meant the volume taken up by a solid object submerged in a fluid that would otherwise have been taken up by said fluid.

 

1. Great..

2. O.o √109 is the displacement, u are correct.. Not about fluids :D

[arnav0506 2,777]

we know that, change in velocity/time is acceleration. which can also be stated as derivative of velocity with respect of time when the time is approching 0. so dv/dt=a integrating both sides we get [integration limit]v=at.

now lets say initial velocity was u and final was v. so just put the values and get v-u=at.

++ spectacular use of integration here :) There is another easier way to derive it though :d Edited July 17, 2016 by arnav0506

[arnav0506 2,777]

I think is this:

a^3 + b^3 = a + b = 3 + 3 = ab6

I'm probably wrong :c

Rekt poor thing.. What basenji said Is right, sorry adriel.. U fail XD (jk)

[arnav0506 2,777]

Lol, read the OP (only grade level 8 or below )

2: distance travelled is 13 km, and displacement (distance from starting point) will be about 10.44 km

3: mass times velocity (mv)

For the other questions, Google knows best

LOL yep I read ur instructions Sir.. But I didn't want grade 8 or below to answer stuff they didn't know, I was seeing if there were any kids who were 9th or above like me :lol: Anyway sorry.

[Total_SkiIl 1,983]

:3

[darshancool 81]

++ spectacular use of integration here :) There is another easier way to derive it though :D

Yes

 We know ,

 

a = v-u

     -----

        t

 

Then , at=v-u

Finally , v=u+at

[arnav0506 2,777]

Q. (I hope you 8th graders know this :unsure: ) solve (108)^2 - (94)^2

Q. A) Show that (a-b)^2= a^2-2ab+b^2

B.) (Time) T=90 sec

(Radius) R=4500 km

Find: Distance travelled.

(Take π=22/7)

Hint- 2πr/t

[arnav0506 2,777]

Yes

 We know ,

 

a = v-u

     -----

        t

 

Then , at=v-u

Finally , v=u+at

++

[darshancool 81]

My big bro has physics exam tomorrow (Monday)

[arnav0506 2,777]

My big bro has physics exam tomorrow (Monday)

Which grade?

[darshancool 81]

Which grade?

Grade 11 (I am just on grade 5, infact the derivation i posted was originally told by him :P )

Edited July 17, 2016 by darshancool

[arnav0506 2,777]

Grade 11

 

oh.. Good Luck to him on my behalf.

[Total_SkiIl 1,983]

Crazy, your topic got sooo popular ^^.