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1. If AB=2
and A--B=3
then how much is "A" square plus "B" square?

2.fill in the __,you can add anything that doesn't involve numbers, like 2_2_2=6-------2+2+2=6 and you can add square root and ()and more..
1__1__1=6
2__2__2=6      i will solve the 4__4__4=6
3__3__3=6      √4+√4+√4=6

4__4__4=6
5__5__5-6
6__6__6=6
7__7__7=6
8__8__8=6
9__9__9=6

 
3.what weighs more, 2 pounds of metal or 2 pounds of feathers? (tricky)

4.good luck with this one.

400 books were given to 4 people,

the first person got 3 times less books than the second person and 100 less than the third person,the second person got 0.2 books from the 4th person.how much books did each person get?

 

 

 

 

5.how much is 1/4:55?

 

6.whats bigger,4 to the power 5 + 4 to the power 4 + 4 to the power 5 OR 4 to the power 6?

 

7. try to remember what your learned.easy question...

what bigger,ninth(1/9) OR 8 to the power -1.

 

8. whats bigger... 1/8 or 7 to the power -2?

9.this one's not a math question but is very hard.

 

what is this human's gender? boy/girl or other?https://www.youtube.com/watch?v=hrYllb93NcQ

 

 

  :P

Edited by yonatanthesuper
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2) 2+2+2

3x3-3

5/5+5

6+6-6

7-7/7

Cube root of 8+ cube root of 8 + cube root of 8

Square root of 9 X square root of 9 - square root of 9

3)They weigh same

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1) 5; A=2, B=1

 

2)

(1+1+1)! = 6

2+2+2=6

3*3-3=6

SR(4)+SR(4)+SR(4)=6

5/5+5=6

6-6+6=6

7-7/7=6

8 - ln(8) / ln(SR(8))=6

-9/SR(9) + 9=6

 

 

3) none of it, same weight

 

 

4)

A=15; B=45; C=115; D=225

 

 

A = 1/3 * B => B = 3*A

A = C - 100 => C = A+100

B = 1/5 * D => D = 5*3*A

 

A + B + C + D = 400

A + 3A + (A+100) + (5*3*A) = 400

20A + 100 = 400

20A = 300

A= 15

...

 

 

Edited by BlackWasp777

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2 pounds of feathers is heavier because you have to carry the weight of what you did to those poor birds as well.

I am your slave now

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1. If AB=2

and A--B=3 then how much is "A" square plus "B" square?

OK, if A*B = 2, then B= 2/A. If A-B = 3, then A - 2/A = 3, or in other words A^2-2 = 3A, or A^2-3A+2=0. The solutions are 2 and 1, using the quadratic formula.  If A = 2, then A^2 + B = A^2 + 2/A = 5. If A = 1, then it is 3. So the problem has two valid solutions.

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OK, if A*B = 2, then B= 2/A. If A-B = 3, then A - 2/A = 3, or in other words A^2-2 = 3A, or A^2-3A+2=0. The solutions are 2 and 1, using the quadratic formula.  If A = 2, then A^2 + B = A^2 + 2/A = 5. If A = 1, then it is 3. So the problem has two valid solutions.

i am not sure what you said there,i didn't learned that stuff,the question i brought up is a random question i got on one of the papers that nobody was able to solve.

Edited by yonatanthesuper

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OK, if A*B = 2, then B= 2/A. If A-B = 3, then A - 2/A = 3, or in other words A^2-2 = 3A, or A^2-3A+2=0. The solutions are 2 and 1, using the quadratic formula. If A = 2, then A^2 + B = A^2 + 2/A = 5. If A = 1, then it is 3. So the problem has two valid solutions.

good lord! *brain exploded due to overload*

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OK, if A*B = 2, then B= 2/A. If A-B = 3, then A - 2/A = 3, or in other words A^2-2 = 3A, or A^2-3A+2=0. The solutions are 2 and 1, using the quadratic formula.  If A = 2, then A^2 + B = A^2 + 2/A = 5. If A = 1, then it is 3. So the problem has two valid solutions.

red part does not look like the given question.

The question was "A - - B = 3"

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